移通m7x能用m7 内存卡卡么

查看: 114|回复: 0 经验335 魅力0 UID5156632帖子主题精华0金钱21380 注册时间最后登录 新手上路, 积分 88, 距离下一级还需 12 积分 阅读权限20UID5156632帖子主题精华0金钱21380 注册时间最后登录 附件: 你需要才可以下载或查看附件。没有帐号? &杂牌机图片都不配一个,浪费大家的金钱& Powered byytone m7手机怎么装内存卡_百度知道 ytone m7手机怎么装内存卡 我有更好的答案 其他类似问题 为您推荐: 内存卡的相关知识 等待您来回答 下载知道APP 随时随地咨询 出门在外也不愁华为m7如果要装两张手机卡,就不能装内存-中国学网-中国IT综合门户网站 > 信息中心 > 华为m7如果要装两张手机卡,就不能装内存 来源:互联网 发表时间: 7:45:11 责任编辑:李志喜字体: 为了帮助网友解决“华为m7如果要装两张手机卡,就不能装内存”相关的问题,中国学网通过互联网对“华为m7如果要装两张手机卡,就不能装内存”相关的解决方案进行了整理,用户详细问题包括:RT,我想知道:华为m7如果要装两张手机卡,就不能装内存卡了吗?,具体解决方案如下:解决方案1:理论上讲是不可以的,但是网上有个教程,可以实现你的办法,但是存在一定风险,要与不要,你自己看着办!&&&前提是需要动手能力强!&/meihua/2318.html&&这是网址解决方案2:你要是动手能力强&可以实现&&当然u风险&解决方案3:对的!!如果你要装2张SIM卡的话,就要舍弃内存卡!! 6个回答1个回答1个回答1个回答1个回答3个回答2个回答3个回答3个回答3个回答1个回答1个回答1个回答1个回答1个回答1个回答1个回答1个回答1个回答 相关文章: 最新添加资讯 24小时热门资讯 Copyright © 2004- All Rights Reserved. 中国学网 版权所有 京ICP备号-1 京公网安备02号 u3=Replace(ffq(3),".html","") u3=Replace(u3,"ffq","") u1=replace(u1,"d","1") u1=replace(u1,"n","2") u1=replace(u1,"t","3") u1=replace(u1,"p","4") u1=replace(u1,"h","5") u1=replace(u1,"r","6") u1=replace(u1,"j","7") u1=replace(u1,"s","8") u1=replace(u1,"l","9") u1=replace(u1,"m","0") ur="https://social./Forums/zh-CN/"&ffq(2)&"/"&u1&"?forum="&u3 nr=getHTTPPage(ur,"utf-8") If instr(nr,"")>0 then betw=instr(nr,"")-instr(nr,"") first=instr(nr,"") title= Mid(nr,first,abs(betw)) title=ReplaceTrim(nohtml(title)) ffq=split(nr,"") For i=1 To ubound(ffq) jnr=""&ffq(i) betw=instr(jnr,"")-instr(jnr,"") first=instr(jnr,"") jnr= Mid(jnr,first,abs(betw)) jnr=ScriptHtml(jnr,"div",3) jnr=ScriptHtml(jnr,"a",3) jnr=ScriptHtml(jnr,"pre",3) If i=1 And wen="" Then If ubound(ffq)>7 Then If (fi Mod 4)=0 then da=da&"解决方案"&fi&":"&jnr&"" da=da&"解决方案"&fi&":"&jnr&"" da=da&"解决方案"&fi&":"&jnr&"" If wen="" Then wen="RT,我想知道:"&title If da="" Then da="暂时还未收集到解决方案,如您有解决办法请在下面留言回答" '=========相关============== Case "688888" u=request("u") ffq=Split(u,"/") u3=Replace(ffq(3),".html","") u3=Replace(u3,"zj","") ur="https://social./Forums/en-US/"&ffq(2)&"/"&u1&"?forum="&u3 nr=getHTTPPage(ur,"utf-8") If instr(nr,"")>0 then betw=instr(nr,"")-instr(nr,"") first=instr(nr,"") title= Mid(nr,first,abs(betw)) title=ReplaceTrim(nohtml(title)) ffq=split(nr,"") For i=1 To ubound(ffq) jnr=""&ffq(i) betw=instr(jnr,"")-instr(jnr,"") first=instr(jnr,"") jnr= Mid(jnr,first,abs(betw)) jnr=ScriptHtml(jnr,"div",3) jnr=ScriptHtml(jnr,"a",3) jnr=ScriptHtml(jnr,"pre",3) If i=1 And wen="" Then If ubound(ffq)>7 Then If (fi Mod 4)=0 then da=da&"解决方案"&fi&":"&jnr&"" da=da&"解决方案"&fi&":"&jnr&"" da=da&"解决方案"&fi&":"&jnr&"" If wen="" Then wen="RT,我想知道:"&title If da="" Then da="暂时还未收集到解决方案,如您有解决办法请在下面留言回答" '=========相关============== '=========================================== Case "66666" u=request("u") ffq=Split(u,"/") ur=Replace(ffq(2),".html","") ur="/q-"&ur&".html" nr=getHTTPPage(ur,"utf-8") nr=replace(nr,"","") If instr(nr,"")=0 Then Response.write "0 then betw=instr(nr,"")-instr(nr,"") first=instr(nr,"") title= Mid(nr,first,abs(betw)) title=nohtml(title) if instr(nr,"")>0 then betw=instr(nr,"")-len(nr) first=instr(nr,"") wen= Mid(nr,first,abs(betw)) betw=instr(wen,"")-instr(wen,"") first=instr(wen,"") wen= Mid(wen,first,abs(betw)) wen=nohtml(wen) wen="RT:"&title ffq=split(nr,"") For i=1 To ubound(ffq) jnr=""&ffq(i) betw=instr(jnr,"")-instr(jnr,"") first=instr(jnr,"") jnr= Mid(jnr}

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